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5/2x=98-x
We move all terms to the left:
5/2x-(98-x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
5/2x-(-1x+98)=0
We get rid of parentheses
5/2x+1x-98=0
We multiply all the terms by the denominator
1x*2x-98*2x+5=0
Wy multiply elements
2x^2-196x+5=0
a = 2; b = -196; c = +5;
Δ = b2-4ac
Δ = -1962-4·2·5
Δ = 38376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{38376}=\sqrt{36*1066}=\sqrt{36}*\sqrt{1066}=6\sqrt{1066}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-196)-6\sqrt{1066}}{2*2}=\frac{196-6\sqrt{1066}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-196)+6\sqrt{1066}}{2*2}=\frac{196+6\sqrt{1066}}{4} $
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