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5/2x=x+6
We move all terms to the left:
5/2x-(x+6)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
5/2x-x-6=0
We multiply all the terms by the denominator
-x*2x-6*2x+5=0
Wy multiply elements
-2x^2-12x+5=0
a = -2; b = -12; c = +5;
Δ = b2-4ac
Δ = -122-4·(-2)·5
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{46}}{2*-2}=\frac{12-2\sqrt{46}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{46}}{2*-2}=\frac{12+2\sqrt{46}}{-4} $
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