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x in (-oo:+oo)
(5/2)*y = (2/5)*a // - (2/5)*a
(5/2)*y-((2/5)*a) = 0
(-2/5)*a+(5/2)*y = 0
5/2*y-2/5*a = 0
x należy do R
x in (-oo:+oo)
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