5/2y=7/y-3

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Solution for 5/2y=7/y-3 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(5/2)*y = 7/y-3 // - 7/y-3

(5/2)*y-(7/y)+3 = 0

(5/2)*y-7*y^-1+3 = 0

5/2*y^1-7*y^-1+3*y^0 = 0

(5/2*y^2+3*y^1-7*y^0)/(y^1) = 0 // * y^2

y^1*(5/2*y^2+3*y^1-7*y^0) = 0

y^1

(5/2)*y^2+3*y-7 = 0

(5/2)*y^2+3*y-7 = 0

DELTA = 3^2-(-7*4*(5/2))

DELTA = 79

DELTA > 0

y = (79^(1/2)-3)/(2*(5/2)) or y = (-79^(1/2)-3)/(2*(5/2))

y = (79^(1/2)-3)/5 or y = (-(79^(1/2)+3))/5

y in { (-(79^(1/2)+3))/5, (79^(1/2)-3)/5}

y in { (-(79^(1/2)+3))/5, (79^(1/2)-3)/5 }

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