5/3(2x-3)(x+1)=10x-5

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Solution for 5/3(2x-3)(x+1)=10x-5 equation: 



5/3(2x-3)(x+1)=10x-5

We move all terms to the left:

5/3(2x-3)(x+1)-(10x-5)=0



Domain of the equation: 3(2x-3)(x+1)!=0

x∈R



We get rid of parentheses

5/3(2x-3)(x+1)-10x+5=0

We multiply parentheses ..

5/3(+2x^2+2x-3x-3)-10x+5=0

We multiply all the terms by the denominator


-10x*3(+2x^2+2x-3x-3)+5*3(+2x^2+2x-3x-3)+5=0

Wy multiply elements

-30x^2(++15x(++5=0

We use the square of the difference formula

-30x^2(+15x(+5=0

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