5/3*(2x-3)(x+1)=10x-5

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Solution for 5/3*(2x-3)(x+1)=10x-5 equation: 


x in (-oo:+oo)

(5/3)*(2*x-3)*(x+1) = 10*x-5 // - 10*x-5

(5/3)*(2*x-3)*(x+1)-(10*x)+5 = 0

(5/3)*(2*x-3)*(x+1)-10*x+5 = 0

5/3*(2*x-3)*(x+1)-10*x+5 = 0

5/3*(2*x-3)*(x+1)-10*x+5 = 0

10/3*x^2-35/3*x-5+5 = 0

10/3*x^2-35/3*x = 0

10/3*x^2-35/3*x = 0

5/3*x*(2*x-7) = 0

2*x-7 = 0 // + 7

2*x = 7 // : 2

x = 7/2

5/3*x*(x-7/2) = 0

5/3*x*(x-7/2) = 0

( 5/3*x )

5/3*x = 0 // : 5/3

x = 0

( x-7/2 )

x-7/2 = 0 // + 7/2

x = 7/2

x in { 0, 7/2 }

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