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5/3y-y=1660
We move all terms to the left:
5/3y-y-(1660)=0
Domain of the equation: 3y!=0We add all the numbers together, and all the variables
y!=0/3
y!=0
y∈R
-1y+5/3y-1660=0
We multiply all the terms by the denominator
-1y*3y-1660*3y+5=0
Wy multiply elements
-3y^2-4980y+5=0
a = -3; b = -4980; c = +5;
Δ = b2-4ac
Δ = -49802-4·(-3)·5
Δ = 24800460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24800460}=\sqrt{4*6200115}=\sqrt{4}*\sqrt{6200115}=2\sqrt{6200115}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4980)-2\sqrt{6200115}}{2*-3}=\frac{4980-2\sqrt{6200115}}{-6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4980)+2\sqrt{6200115}}{2*-3}=\frac{4980+2\sqrt{6200115}}{-6} $
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