5/3+10/y=3y-4

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Solution for 5/3+10/y=3y-4 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

10/y+5/3 = 3*y-4 // - 3*y-4

10/y-(3*y)+5/3+4 = 0

10/y-3*y+5/3+4 = 0

10*y^-1-3*y^1+17/3*y^0 = 0

(17/3*y^1-3*y^2+10*y^0)/(y^1) = 0 // * y^2

y^1*(17/3*y^1-3*y^2+10*y^0) = 0

y^1

(17/3)*y-3*y^2+10 = 0

(17/3)*y-3*y^2+10 = 0

DELTA = (17/3)^2-(-3*4*10)

DELTA = 1369/9

DELTA > 0

y = ((1369/9)^(1/2)-(17/3))/(-3*2) or y = (-(17/3)-(1369/9)^(1/2))/(-3*2)

y = -10/9 or y = 3

y in { -10/9, 3} 

y in { -10/9, 3 }

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