5/3-4x=40/x-6x

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Solution for 5/3-4x=40/x-6x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5/3-(4*x) = 40/x-(6*x) // - 40/x-(6*x)

6*x-(4*x)-(40/x)+5/3 = 0

6*x-4*x-40*x^-1+5/3 = 0

2*x^1-40*x^-1+5/3*x^0 = 0

(2*x^2+5/3*x^1-40*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2+5/3*x^1-40*x^0) = 0

x^1

2*x^2+(5/3)*x-40 = 0

2*x^2+(5/3)*x-40 = 0

DELTA = (5/3)^2-(-40*2*4)

DELTA = 2905/9

DELTA > 0

x = ((2905/9)^(1/2)-(5/3))/(2*2) or x = (-(5/3)-(2905/9)^(1/2))/(2*2)

x = ((2905/9)^(1/2)-5/3)/4 or x = (-((2905/9)^(1/2)+5/3))/4

x in { (-((2905/9)^(1/2)+5/3))/4, ((2905/9)^(1/2)-5/3)/4}

x in { (-((2905/9)^(1/2)+5/3))/4, ((2905/9)^(1/2)-5/3)/4 }

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