5/3=(7x-9)/(9-3x)

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Solution for 5/3=(7x-9)/(9-3x) equation: 



5/3=(7x-9)/(9-3x)

We move all terms to the left:

5/3-((7x-9)/(9-3x))=0



Domain of the equation: (9-3x))!=0

We move all terms containing x to the left, all other terms to the right

-3x)!=-9

x!=-9/1

x!=-9

x∈R



We add all the numbers together, and all the variables

-((7x-9)/(-3x+9))+5/3=0

We calculate fractions


(-((7x-9)*3)/(-9x)+(-15x)/(-9x)=0



We calculate terms in parentheses: +(-((7x-9)*3)/(-9x)+(-15x)/(-9x), so:

-((7x-9)*3)/(-9x)+(-15x)/(-9x

We calculate fractions


(-((7x-9)*3)*(-9x)/((-9x)*(-9x)+((-15x)*(-9x))/((-9x)*(-9x)



We calculate terms in parentheses: +(-((7x-9)*3)*(-9x)/((-9x)*(-9x)+((-15x)*(-9x))/((-9x)*(-9x), so:

-((7x-9)*3)*(-9x)/((-9x)*(-9x)+((-15x)*(-9x))/((-9x)*(-9x

We can not solve this equation

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