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5/3=(7x-9)/(9-3x)
We move all terms to the left:
5/3-((7x-9)/(9-3x))=0
Domain of the equation: (9-3x))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-3x)!=-9
x!=-9/1
x!=-9
x∈R
-((7x-9)/(-3x+9))+5/3=0
We calculate fractions
(-((7x-9)*3)/(-9x)+(-15x)/(-9x)=0
We calculate terms in parentheses: +(-((7x-9)*3)/(-9x)+(-15x)/(-9x), so:
-((7x-9)*3)/(-9x)+(-15x)/(-9x
We calculate fractions
(-((7x-9)*3)*(-9x)/((-9x)*(-9x)+((-15x)*(-9x))/((-9x)*(-9x)
We calculate terms in parentheses: +(-((7x-9)*3)*(-9x)/((-9x)*(-9x)+((-15x)*(-9x))/((-9x)*(-9x), so:
-((7x-9)*3)*(-9x)/((-9x)*(-9x)+((-15x)*(-9x))/((-9x)*(-9x
We can not solve this equation
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