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5/3d+2/3=5+d/2d
We move all terms to the left:
5/3d+2/3-(5+d/2d)=0
Domain of the equation: 3d!=0
d!=0/3
d!=0
d∈R
Domain of the equation: 2d)!=0We add all the numbers together, and all the variables
d!=0/1
d!=0
d∈R
5/3d-(d/2d+5)+2/3=0
We get rid of parentheses
5/3d-d/2d-5+2/3=0
We calculate fractions
(-27d^2)/54d^2+10d/54d^2+4d/54d^2-5=0
We multiply all the terms by the denominator
(-27d^2)+10d+4d-5*54d^2=0
We add all the numbers together, and all the variables
(-27d^2)+14d-5*54d^2=0
Wy multiply elements
(-27d^2)-270d^2+14d=0
We get rid of parentheses
-27d^2-270d^2+14d=0
We add all the numbers together, and all the variables
-297d^2+14d=0
a = -297; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-297)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-297}=\frac{-28}{-594} =14/297 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-297}=\frac{0}{-594} =0 $
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