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5/3k+1/k=-2
We move all terms to the left:
5/3k+1/k-(-2)=0
Domain of the equation: 3k!=0
k!=0/3
k!=0
k∈R
Domain of the equation: k!=0We add all the numbers together, and all the variables
k∈R
5/3k+1/k+2=0
We calculate fractions
5k/3k^2+3k/3k^2+2=0
We multiply all the terms by the denominator
5k+3k+2*3k^2=0
We add all the numbers together, and all the variables
8k+2*3k^2=0
Wy multiply elements
6k^2+8k=0
a = 6; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·6·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*6}=\frac{-16}{12} =-1+1/3 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*6}=\frac{0}{12} =0 $
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