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5/3n-1=3/2n+4
We move all terms to the left:
5/3n-1-(3/2n+4)=0
Domain of the equation: 3n!=0
n!=0/3
n!=0
n∈R
Domain of the equation: 2n+4)!=0We get rid of parentheses
n∈R
5/3n-3/2n-4-1=0
We calculate fractions
10n/6n^2+(-9n)/6n^2-4-1=0
We add all the numbers together, and all the variables
10n/6n^2+(-9n)/6n^2-5=0
We multiply all the terms by the denominator
10n+(-9n)-5*6n^2=0
Wy multiply elements
-30n^2+10n+(-9n)=0
We get rid of parentheses
-30n^2+10n-9n=0
We add all the numbers together, and all the variables
-30n^2+n=0
a = -30; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-30)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-30}=\frac{-2}{-60} =1/30 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-30}=\frac{0}{-60} =0 $
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