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5/3x+2=2x-1
We move all terms to the left:
5/3x+2-(2x-1)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
5/3x-2x+1+2=0
We multiply all the terms by the denominator
-2x*3x+1*3x+2*3x+5=0
Wy multiply elements
-6x^2+3x+6x+5=0
We add all the numbers together, and all the variables
-6x^2+9x+5=0
a = -6; b = 9; c = +5;
Δ = b2-4ac
Δ = 92-4·(-6)·5
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{201}}{2*-6}=\frac{-9-\sqrt{201}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{201}}{2*-6}=\frac{-9+\sqrt{201}}{-12} $
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