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5/3x+4=-2/4x+1
We move all terms to the left:
5/3x+4-(-2/4x+1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x+1)!=0We get rid of parentheses
x∈R
5/3x+2/4x-1+4=0
We calculate fractions
20x/12x^2+6x/12x^2-1+4=0
We add all the numbers together, and all the variables
20x/12x^2+6x/12x^2+3=0
We multiply all the terms by the denominator
20x+6x+3*12x^2=0
We add all the numbers together, and all the variables
26x+3*12x^2=0
Wy multiply elements
36x^2+26x=0
a = 36; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·36·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*36}=\frac{-52}{72} =-13/18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*36}=\frac{0}{72} =0 $
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