5/3x-2=10/x

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Solution for 5/3x-2=10/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(5/3)*x-2 = 10/x // - 10/x

(5/3)*x-(10/x)-2 = 0

(5/3)*x-10*x^-1-2 = 0

5/3*x^1-10*x^-1-2*x^0 = 0

(5/3*x^2-2*x^1-10*x^0)/(x^1) = 0 // * x^2

x^1*(5/3*x^2-2*x^1-10*x^0) = 0

x^1

(5/3)*x^2-2*x-10 = 0

(5/3)*x^2-2*x-10 = 0

DELTA = (-2)^2-(-10*4*(5/3))

DELTA = 212/3

DELTA > 0

x = ((212/3)^(1/2)+2)/(2*(5/3)) or x = (2-(212/3)^(1/2))/(2*(5/3))

x = 3/10*((212/3)^(1/2)+2) or x = 3/10*(2-(212/3)^(1/2))

x in { 3/10*(2-(212/3)^(1/2)), 3/10*((212/3)^(1/2)+2)}

x in { 3/10*(2-(212/3)^(1/2)), 3/10*((212/3)^(1/2)+2) }

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