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5/3x-4=16
We move all terms to the left:
5/3x-4-(16)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
5/3x-20=0
We multiply all the terms by the denominator
-20*3x+5=0
Wy multiply elements
-60x+5=0
We move all terms containing x to the left, all other terms to the right
-60x=-5
x=-5/-60
x=1/12
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