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5/3x=5x-19
We move all terms to the left:
5/3x-(5x-19)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
5/3x-5x+19=0
We multiply all the terms by the denominator
-5x*3x+19*3x+5=0
Wy multiply elements
-15x^2+57x+5=0
a = -15; b = 57; c = +5;
Δ = b2-4ac
Δ = 572-4·(-15)·5
Δ = 3549
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3549}=\sqrt{169*21}=\sqrt{169}*\sqrt{21}=13\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-13\sqrt{21}}{2*-15}=\frac{-57-13\sqrt{21}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+13\sqrt{21}}{2*-15}=\frac{-57+13\sqrt{21}}{-30} $
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