5/3y-12=7

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Solution for 5/3y-12=7 equation: 



5/3y-12=7

We move all terms to the left:

5/3y-12-(7)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We add all the numbers together, and all the variables

5/3y-19=0

We multiply all the terms by the denominator


-19*3y+5=0

Wy multiply elements

-57y+5=0

We move all terms containing y to the left, all other terms to the right

-57y=-5

y=-5/-57

y=5/57

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