5/3y=27

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Solution for 5/3y=27 equation: 



5/3y=27

We move all terms to the left:

5/3y-(27)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We multiply all the terms by the denominator


-27*3y+5=0

Wy multiply elements

-81y+5=0

We move all terms containing y to the left, all other terms to the right

-81y=-5

y=-5/-81

y=5/81

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