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5/3z+12=9
We move all terms to the left:
5/3z+12-(9)=0
Domain of the equation: 3z!=0We add all the numbers together, and all the variables
z!=0/3
z!=0
z∈R
5/3z+3=0
We multiply all the terms by the denominator
3*3z+5=0
Wy multiply elements
9z+5=0
We move all terms containing z to the left, all other terms to the right
9z=-5
z=-5/9
z=-5/9
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