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5/3z=3
We move all terms to the left:
5/3z-(3)=0
Domain of the equation: 3z!=0We multiply all the terms by the denominator
z!=0/3
z!=0
z∈R
-3*3z+5=0
Wy multiply elements
-9z+5=0
We move all terms containing z to the left, all other terms to the right
-9z=-5
z=-5/-9
z=5/9
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