5/4(2-k)=2(3k-1)-2/3k

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Solution for 5/4(2-k)=2(3k-1)-2/3k equation:



5/4(2-k)=2(3k-1)-2/3k
We move all terms to the left:
5/4(2-k)-(2(3k-1)-2/3k)=0
Domain of the equation: 4(2-k)!=0
k∈R
Domain of the equation: 3k)!=0
k!=0/1
k!=0
k∈R
We add all the numbers together, and all the variables
5/4(-1k+2)-(2(3k-1)-2/3k)=0
We calculate fractions
15k/(24k^2-4k)+(-(6k-8k0)/(24k^2-4k)=0
We calculate terms in parentheses: +(-(6k-8k0)/(24k^2-4k), so:
-(6k-8k0)/(24k^2-4k
We add all the numbers together, and all the variables
-(-2k)/(24k^2-4k
We multiply all the terms by the denominator
-(-2k)
We get rid of parentheses
2k
Back to the equation:
+(2k)
We add all the numbers together, and all the variables
2k+15k/(24k^2-4k)=0
We multiply all the terms by the denominator
2k*(24k^2-4k)+15k=0
We add all the numbers together, and all the variables
15k+2k*(24k^2-4k)=0
We multiply parentheses
48k^3-8k^2+15k=0
We do not support ekpression: k^3

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