5/4(2-k)=2(3k-1)-2/4k

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Solution for 5/4(2-k)=2(3k-1)-2/4k equation: 



5/4(2-k)=2(3k-1)-2/4k

We move all terms to the left:

5/4(2-k)-(2(3k-1)-2/4k)=0



Domain of the equation: 4(2-k)!=0

k∈R





Domain of the equation: 4k)!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

5/4(-1k+2)-(2(3k-1)-2/4k)=0

We calculate fractions


20k/(32k^2-4k)+(-(6k-8k0)/(32k^2-4k)=0



We calculate terms in parentheses: +(-(6k-8k0)/(32k^2-4k), so:

-(6k-8k0)/(32k^2-4k

We add all the numbers together, and all the variables

-(-2k)/(32k^2-4k

We multiply all the terms by the denominator


-(-2k)

We get rid of parentheses

2k

Back to the equation:

+(2k)



We add all the numbers together, and all the variables

2k+20k/(32k^2-4k)=0

We multiply all the terms by the denominator


2k*(32k^2-4k)+20k=0

We add all the numbers together, and all the variables

20k+2k*(32k^2-4k)=0

We multiply parentheses

64k^3-8k^2+20k=0

We do not support ekpression: k^3

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