5/4(20x+12)=-35

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Solution for 5/4(20x+12)=-35 equation:



5/4(20x+12)=-35
We move all terms to the left:
5/4(20x+12)-(-35)=0
Domain of the equation: 4(20x+12)!=0
x∈R
We add all the numbers together, and all the variables
5/4(20x+12)+35=0
We multiply all the terms by the denominator
35*4(20x+12)+5=0
Wy multiply elements
140x(2+5=0

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