5/4(20x-12)=-35

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Solution for 5/4(20x-12)=-35 equation: 



5/4(20x-12)=-35

We move all terms to the left:

5/4(20x-12)-(-35)=0



Domain of the equation: 4(20x-12)!=0

x∈R



We add all the numbers together, and all the variables

5/4(20x-12)+35=0

We multiply all the terms by the denominator


35*4(20x-12)+5=0

Wy multiply elements

140x(2+5=0

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