5/4(20z+12)=-35

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Solution for 5/4(20z+12)=-35 equation: 



5/4(20z+12)=-35

We move all terms to the left:

5/4(20z+12)-(-35)=0



Domain of the equation: 4(20z+12)!=0

z∈R



We add all the numbers together, and all the variables

5/4(20z+12)+35=0

We multiply all the terms by the denominator


35*4(20z+12)+5=0

Wy multiply elements

140z(2+5=0

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