5/4(7b+3)=4b-12

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Solution for 5/4(7b+3)=4b-12 equation: 



5/4(7b+3)=4b-12

We move all terms to the left:

5/4(7b+3)-(4b-12)=0



Domain of the equation: 4(7b+3)!=0

b∈R



We get rid of parentheses

5/4(7b+3)-4b+12=0

We multiply all the terms by the denominator


-4b*4(7b+3)+12*4(7b+3)+5=0

Wy multiply elements

-16b^2(7+48b(7+5=0

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