5/4(g+3)=2/3(7-g)

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Solution for 5/4(g+3)=2/3(7-g) equation: 



5/4(g+3)=2/3(7-g)

We move all terms to the left:

5/4(g+3)-(2/3(7-g))=0



Domain of the equation: 4(g+3)!=0

g∈R





Domain of the equation: 3(7-g))!=0

g∈R



We add all the numbers together, and all the variables

5/4(g+3)-(2/3(-1g+7))=0

We calculate fractions


(15g(-)/(4(g+3)*3(-1g+7)))+(-8gg/(4(g+3)*3(-1g+7)))=0



We calculate terms in parentheses: +(15g(-)/(4(g+3)*3(-1g+7))), so:

15g(-)/(4(g+3)*3(-1g+7))

We add all the numbers together, and all the variables

15g0/(4(g+3)*3(-1g+7))

We multiply all the terms by the denominator


15g0

We add all the numbers together, and all the variables

15g

Back to the equation:

+(15g)





We calculate terms in parentheses: +(-8gg/(4(g+3)*3(-1g+7))), so:

-8gg/(4(g+3)*3(-1g+7))

We multiply all the terms by the denominator


-8gg

Back to the equation:

+(-8gg)



We get rid of parentheses

15g-8gg=0

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