5/4n=n-3/n-4

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Solution for 5/4n=n-3/n-4 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

(5/4)*n = n-(3/n)-4 // - n-(3/n)-4

(5/4)*n-n+3/n+4 = 0

1/4*n^1+3*n^-1+4*n^0 = 0

(1/4*n^2+4*n^1+3*n^0)/(n^1) = 0 // * n^2

n^1*(1/4*n^2+4*n^1+3*n^0) = 0

n^1

(1/4)*n^2+4*n+3 = 0

(1/4)*n^2+4*n+3 = 0

DELTA = 4^2-(3*4*(1/4))

DELTA = 13

DELTA > 0

n = (13^(1/2)-4)/(2*(1/4)) or n = (-13^(1/2)-4)/(2*(1/4))

n = 2*(13^(1/2)-4) or n = -2*(13^(1/2)+4)

n in { -2*(13^(1/2)+4), 2*(13^(1/2)-4)} 

n in { -2*(13^(1/2)+4), 2*(13^(1/2)-4) }

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