5/4t+2/t=5

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Solution for 5/4t+2/t=5 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

(5/4)*t+2/t = 5 // - 5

(5/4)*t+2/t-5 = 0

5/4*t^1+2*t^-1-5*t^0 = 0

(5/4*t^2-5*t^1+2*t^0)/(t^1) = 0 // * t^2

t^1*(5/4*t^2-5*t^1+2*t^0) = 0

t^1

(5/4)*t^2-5*t+2 = 0

(5/4)*t^2-5*t+2 = 0

DELTA = (-5)^2-(2*4*(5/4))

DELTA = 15

DELTA > 0

t = (15^(1/2)+5)/(2*(5/4)) or t = (5-15^(1/2))/(2*(5/4))

t = 2/5*(15^(1/2)+5) or t = 2/5*(5-15^(1/2))

t in { 2/5*(5-15^(1/2)), 2/5*(15^(1/2)+5)} 

t in { 2/5*(5-15^(1/2)), 2/5*(15^(1/2)+5) }

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