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5/4x+(7/2)=2x-(5/2)
We move all terms to the left:
5/4x+(7/2)-(2x-(5/2))=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
5/4x-(2x-(+5/2))+(+7/2)=0
We get rid of parentheses
5/4x-(2x-(+5/2))+7/2=0
We calculate fractions
()/16x^2+(-(2x-(+5*4x)/16x^2+28x/16x^2=0
We can not solve this equation
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