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5/4x+16=x
We move all terms to the left:
5/4x+16-(x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-1x+5/4x+16=0
We multiply all the terms by the denominator
-1x*4x+16*4x+5=0
Wy multiply elements
-4x^2+64x+5=0
a = -4; b = 64; c = +5;
Δ = b2-4ac
Δ = 642-4·(-4)·5
Δ = 4176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4176}=\sqrt{144*29}=\sqrt{144}*\sqrt{29}=12\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-12\sqrt{29}}{2*-4}=\frac{-64-12\sqrt{29}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+12\sqrt{29}}{2*-4}=\frac{-64+12\sqrt{29}}{-8} $
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