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5/4x+3/8=2+1/12x
We move all terms to the left:
5/4x+3/8-(2+1/12x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 12x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5/4x-(1/12x+2)+3/8=0
We get rid of parentheses
5/4x-1/12x-2+3/8=0
We calculate fractions
144x^2/3072x^2+3840x/3072x^2+(-256x)/3072x^2-2=0
We multiply all the terms by the denominator
144x^2+3840x+(-256x)-2*3072x^2=0
Wy multiply elements
144x^2-6144x^2+3840x+(-256x)=0
We get rid of parentheses
144x^2-6144x^2+3840x-256x=0
We add all the numbers together, and all the variables
-6000x^2+3584x=0
a = -6000; b = 3584; c = 0;
Δ = b2-4ac
Δ = 35842-4·(-6000)·0
Δ = 12845056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12845056}=3584$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3584)-3584}{2*-6000}=\frac{-7168}{-12000} =224/375 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3584)+3584}{2*-6000}=\frac{0}{-12000} =0 $
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