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5/4x+6=3/2x+2
We move all terms to the left:
5/4x+6-(3/2x+2)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x+2)!=0We get rid of parentheses
x∈R
5/4x-3/2x-2+6=0
We calculate fractions
10x/8x^2+(-12x)/8x^2-2+6=0
We add all the numbers together, and all the variables
10x/8x^2+(-12x)/8x^2+4=0
We multiply all the terms by the denominator
10x+(-12x)+4*8x^2=0
Wy multiply elements
32x^2+10x+(-12x)=0
We get rid of parentheses
32x^2+10x-12x=0
We add all the numbers together, and all the variables
32x^2-2x=0
a = 32; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·32·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*32}=\frac{0}{64} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*32}=\frac{4}{64} =1/16 $
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