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5/4x-2/5x=13=21
We move all terms to the left:
5/4x-2/5x-(13)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
25x/20x^2+(-8x)/20x^2-13=0
We multiply all the terms by the denominator
25x+(-8x)-13*20x^2=0
Wy multiply elements
-260x^2+25x+(-8x)=0
We get rid of parentheses
-260x^2+25x-8x=0
We add all the numbers together, and all the variables
-260x^2+17x=0
a = -260; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-260)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-260}=\frac{-34}{-520} =17/260 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-260}=\frac{0}{-520} =0 $
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