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5/4x-6/x-1=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: x!=0We calculate fractions
x∈R
5x/4x^2+(-24x)/4x^2-1=0
We multiply all the terms by the denominator
5x+(-24x)-1*4x^2=0
Wy multiply elements
-4x^2+5x+(-24x)=0
We get rid of parentheses
-4x^2+5x-24x=0
We add all the numbers together, and all the variables
-4x^2-19x=0
a = -4; b = -19; c = 0;
Δ = b2-4ac
Δ = -192-4·(-4)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-19}{2*-4}=\frac{0}{-8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+19}{2*-4}=\frac{38}{-8} =-4+3/4 $
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