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5/4x-6=2/x-9
We move all terms to the left:
5/4x-6-(2/x-9)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: x-9)!=0We get rid of parentheses
x∈R
5/4x-2/x+9-6=0
We calculate fractions
5x/4x^2+(-8x)/4x^2+9-6=0
We add all the numbers together, and all the variables
5x/4x^2+(-8x)/4x^2+3=0
We multiply all the terms by the denominator
5x+(-8x)+3*4x^2=0
Wy multiply elements
12x^2+5x+(-8x)=0
We get rid of parentheses
12x^2+5x-8x=0
We add all the numbers together, and all the variables
12x^2-3x=0
a = 12; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·12·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*12}=\frac{6}{24} =1/4 $
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