5/4x-7/2=3/2x+14

Solution for 5/4x-7/2=3/2x+14 equation:

5/4x-7/2=3/2x+14

We move all terms to the left:

5/4x-7/2-(3/2x+14)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x+14)!=0

x∈R


We get rid of parentheses

5/4x-3/2x-14-7/2=0

We calculate fractions


40x/32x^2+(-12x)/32x^2+(-28x)/32x^2-14=0

We multiply all the terms by the denominator


40x+(-12x)+(-28x)-14*32x^2=0

Wy multiply elements

-448x^2+40x+(-12x)+(-28x)=0

We get rid of parentheses

-448x^2+40x-12x-28x=0

We add all the numbers together, and all the variables

-448x^2=0

a = -448; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-448)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-896}=0$