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5/4x-9=3/2x-14
We move all terms to the left:
5/4x-9-(3/2x-14)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x-14)!=0We get rid of parentheses
x∈R
5/4x-3/2x+14-9=0
We calculate fractions
10x/8x^2+(-12x)/8x^2+14-9=0
We add all the numbers together, and all the variables
10x/8x^2+(-12x)/8x^2+5=0
We multiply all the terms by the denominator
10x+(-12x)+5*8x^2=0
Wy multiply elements
40x^2+10x+(-12x)=0
We get rid of parentheses
40x^2+10x-12x=0
We add all the numbers together, and all the variables
40x^2-2x=0
a = 40; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·40·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*40}=\frac{0}{80} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*40}=\frac{4}{80} =1/20 $
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