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5/4x=2.5x+6
We move all terms to the left:
5/4x-(2.5x+6)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
5/4x-2.5x-6=0
We multiply all the terms by the denominator
-(2.5x)*4x-6*4x+5=0
We add all the numbers together, and all the variables
-(+2.5x)*4x-6*4x+5=0
We multiply parentheses
-8x^2-6*4x+5=0
Wy multiply elements
-8x^2-24x+5=0
a = -8; b = -24; c = +5;
Δ = b2-4ac
Δ = -242-4·(-8)·5
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{46}}{2*-8}=\frac{24-4\sqrt{46}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{46}}{2*-8}=\frac{24+4\sqrt{46}}{-16} $
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