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5/4x=2x
We move all terms to the left:
5/4x-(2x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-2x+5/4x=0
We multiply all the terms by the denominator
-2x*4x+5=0
Wy multiply elements
-8x^2+5=0
a = -8; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-8)·5
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{10}}{2*-8}=\frac{0-4\sqrt{10}}{-16} =-\frac{4\sqrt{10}}{-16} =-\frac{\sqrt{10}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{10}}{2*-8}=\frac{0+4\sqrt{10}}{-16} =\frac{4\sqrt{10}}{-16} =\frac{\sqrt{10}}{-4} $
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