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5/4x=x+2
We move all terms to the left:
5/4x-(x+2)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
5/4x-x-2=0
We multiply all the terms by the denominator
-x*4x-2*4x+5=0
Wy multiply elements
-4x^2-8x+5=0
a = -4; b = -8; c = +5;
Δ = b2-4ac
Δ = -82-4·(-4)·5
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-12}{2*-4}=\frac{-4}{-8} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+12}{2*-4}=\frac{20}{-8} =-2+1/2 $
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