5/6(-12y+30)=-3(4y-3)

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Solution for 5/6(-12y+30)=-3(4y-3) equation: 



5/6(-12y+30)=-3(4y-3)

We move all terms to the left:

5/6(-12y+30)-(-3(4y-3))=0



Domain of the equation: 6(-12y+30)!=0

y∈R



We multiply all the terms by the denominator


-((-3(4y-3)))*6(-12y+30)+5=0



We calculate terms in parentheses: -((-3(4y-3)))*6(-12y+30), so:

(-3(4y-3)))*6(-12y+30

We add all the numbers together, and all the variables

-12y+(-3(4y-3)))*6(+30

Back to the equation:

-(-12y+(-3(4y-3)))*6(+30)



We add all the numbers together, and all the variables

-(-12y+(-3(4y-3)))*630+5=0

We move all terms containing y to the left, all other terms to the right

-(-12y+(-3(4y-3)))*630=-5

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