5/6(1-x)-7/6(x-2)+1/6=1/3(2x-1)+x

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Solution for 5/6(1-x)-7/6(x-2)+1/6=1/3(2x-1)+x equation:



5/6(1-x)-7/6(x-2)+1/6=1/3(2x-1)+x
We move all terms to the left:
5/6(1-x)-7/6(x-2)+1/6-(1/3(2x-1)+x)=0
Domain of the equation: 6(1-x)!=0
x∈R
Domain of the equation: 6(x-2)!=0
x∈R
Domain of the equation: 3(2x-1)+x)!=0
x∈R
We add all the numbers together, and all the variables
5/6(-1x+1)-7/6(x-2)-(1/3(2x-1)+x)+1/6=0
We calculate fractions
We do not support expression: x^2(x

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