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5/6(12k+30)=2k+17
We move all terms to the left:
5/6(12k+30)-(2k+17)=0
Domain of the equation: 6(12k+30)!=0We get rid of parentheses
k∈R
5/6(12k+30)-2k-17=0
We multiply all the terms by the denominator
-2k*6(12k+30)-17*6(12k+30)+5=0
Wy multiply elements
-12k^2(1-102k(1+5=0
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