5/6(2x+1)=3/4x+7

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Solution for 5/6(2x+1)=3/4x+7 equation: 



5/6(2x+1)=3/4x+7

We move all terms to the left:

5/6(2x+1)-(3/4x+7)=0



Domain of the equation: 6(2x+1)!=0

x∈R





Domain of the equation: 4x+7)!=0

x∈R



We get rid of parentheses

5/6(2x+1)-3/4x-7=0

We calculate fractions


20x/(48x^2+24x)+(-18x2/(48x^2+24x)-7=0

We calculate fractions

We do not support expression: x^3

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