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5/6(2x-1)=-1/3x
We move all terms to the left:
5/6(2x-1)-(-1/3x)=0
Domain of the equation: 6(2x-1)!=0
x∈R
Domain of the equation: 3x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
5/6(2x-1)+1/3x=0
We calculate fractions
15x/(36x^2-18x)+(6x2/(36x^2-18x)=0
We calculate terms in parentheses: +(6x2/(36x^2-18x), so:determiningTheFunctionDomain 6x^2+15x/(36x^2-18x)=0
6x2/(36x^2-18x
We multiply all the terms by the denominator
6x2
We add all the numbers together, and all the variables
6x^2
Back to the equation:
+(6x^2)
We multiply all the terms by the denominator
6x^2*(36x^2-18x)+15x=0
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