5/6(36-12x)=2/5(15x+5)

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Solution for 5/6(36-12x)=2/5(15x+5) equation: 



5/6(36-12x)=2/5(15x+5)

We move all terms to the left:

5/6(36-12x)-(2/5(15x+5))=0



Domain of the equation: 6(36-12x)!=0

x∈R





Domain of the equation: 5(15x+5))!=0

x∈R



We add all the numbers together, and all the variables

5/6(-12x+36)-(2/5(15x+5))=0

We calculate fractions


(25x1/(6(-12x+36)*5(15x+5)))+(-12x0/(6(-12x+36)*5(15x+5)))=0



We calculate terms in parentheses: +(25x1/(6(-12x+36)*5(15x+5))), so:

25x1/(6(-12x+36)*5(15x+5))

We multiply all the terms by the denominator


25x1

We add all the numbers together, and all the variables

25x

Back to the equation:

+(25x)





We calculate terms in parentheses: +(-12x0/(6(-12x+36)*5(15x+5))), so:

-12x0/(6(-12x+36)*5(15x+5))

We multiply all the terms by the denominator


-12x0

We add all the numbers together, and all the variables

-12x

Back to the equation:

+(-12x)



We get rid of parentheses

25x-12x=0

We add all the numbers together, and all the variables

13x=0

x=0/13

x=0

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