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x in (-oo:+oo)
(5/6)*(3*x+10) = (5/2)*(x+3)+5/6 // - (5/2)*(x+3)+5/6
(5/6)*(3*x+10)-((5/2)*(x+3))-(5/6) = 0
(5/6)*(3*x+10)+(-5/2)*(x+3)-5/6 = 0
5/6*(3*x+10)-5/2*(x+3)-5/6 = 0
(5/6*6*(3*x+10))/6+(-5/2*6*(x+3))/6-5/6 = 0
5/6*6*(3*x+10)-5/2*6*(x+3)-5 = 0
5-5 = 0
0 = 0
0/6 = 0
0/6 = 0 // * 6
0 = 0
x belongs to the empty set
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